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y=4y^2-16y+7
We move all terms to the left:
y-(4y^2-16y+7)=0
We get rid of parentheses
-4y^2+y+16y-7=0
We add all the numbers together, and all the variables
-4y^2+17y-7=0
a = -4; b = 17; c = -7;
Δ = b2-4ac
Δ = 172-4·(-4)·(-7)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{177}}{2*-4}=\frac{-17-\sqrt{177}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{177}}{2*-4}=\frac{-17+\sqrt{177}}{-8} $
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